Showing posts with label this. Show all posts
Showing posts with label this. Show all posts
Monday, May 27, 2013
Make this Simple Delay ON Timer Circuit Application Note Included
The post explains a simple delay ON circuit which allows the connected load at the output to be switched ON with some predetermined delay after power switch ON.
The explained circuit can be used for all applications which calls for an initial delay ON feature for the connected load after the mains power is switched ON.
The shown diagram is pretty straightforward yet provides the necessary actions very impressively, moreover the delay period is variable making the set up extremely useful for the proposed applications.
The functioning can be understood with the following points:
Assuming the load which requires the delay ON action being connected across the relay contacts, when power is switched ON, the 12V DC passes via R2 but is unable to reach the base of T1 because initially, C2 acts as a short across ground.
The voltage thus passes through R2, gets dropped to relevant limits and starts charging C2.
Once C2 charges up to a level which develops a potential of 0.3 to 0.6V (+ zener voltage) at the base of T1, T1 is instantly switched ON, toggling T2, and the relay subsequently....finally the load gets switched ON too.
The above process induces the required delay for switching ON the load.
The delay period may be set by appropriately selecting the values of R2 and C2.
R1 ensures that C2 quickly discharges through it so that the circuit attains the stand by position as soon as possible.
D3 blocks the charge from reaching the base of T1.

Parts List
R1 = 610K
R2 = 330K
R3= 10K
R4 = 1K
D1 = 3V zener diode
D2 = 1N4007
D3 = 1N4148
T1 = BC547
T2 = BC557
C2 = 33uF/25V
Relay = SPDT, 12V/400 Ohms
Application Note
Lets learn how the above circuit becomes applicable for solving the following presented issue by one of the keen followers of this blog, Mr. Nishant.

The explained circuit can be used for all applications which calls for an initial delay ON feature for the connected load after the mains power is switched ON.
The shown diagram is pretty straightforward yet provides the necessary actions very impressively, moreover the delay period is variable making the set up extremely useful for the proposed applications.
The functioning can be understood with the following points:
Assuming the load which requires the delay ON action being connected across the relay contacts, when power is switched ON, the 12V DC passes via R2 but is unable to reach the base of T1 because initially, C2 acts as a short across ground.
The voltage thus passes through R2, gets dropped to relevant limits and starts charging C2.
Once C2 charges up to a level which develops a potential of 0.3 to 0.6V (+ zener voltage) at the base of T1, T1 is instantly switched ON, toggling T2, and the relay subsequently....finally the load gets switched ON too.
The above process induces the required delay for switching ON the load.
The delay period may be set by appropriately selecting the values of R2 and C2.
R1 ensures that C2 quickly discharges through it so that the circuit attains the stand by position as soon as possible.
D3 blocks the charge from reaching the base of T1.

Parts List
R1 = 610K
R2 = 330K
R3= 10K
R4 = 1K
D1 = 3V zener diode
D2 = 1N4007
D3 = 1N4148
T1 = BC547
T2 = BC557
C2 = 33uF/25V
Relay = SPDT, 12V/400 Ohms
Application Note
Lets learn how the above circuit becomes applicable for solving the following presented issue by one of the keen followers of this blog, Mr. Nishant.
Hello Sir,
I have a 1KVA automatic voltage stabilizer.It has one defect that when it is switched on, very high voltage is outputted for about 1.5s (therefore cfls and bulb got fused frequently) after that the voltage becomes OK. I have opened the stabilizer it consist of an auto-transformer,4 24V relay each relay connected to a separate circuit(each consisting of 10K preset,BC547,zener diode,BDX53BFP npn darlington pair transistor IC,220uF/63v capacitor,100uF/40V capacitor ,4 diodes and some resistors).These circuits are powered by a step down transformer and output of these circuit are taken across corresponding 100uF/40V capacitor and fed to corresponding relay.What to do in order to tackle the problem.please help me.Hand drawn circuit diagram is attached.
Solution:
The problem in the above circuit might be due to two reasons: one of the relays is switching ON momentarily connecting the wrong contacts with the output, or one of the responsible relays is settling down with the correct voltages a little while after power switch ON.
Since there are more than one relay, tracing out the fault and correcting it can be a bit tedious......the circuit of a delay ON timer explained in the above article could be actually very effective for the discussed purpose.
The connections are rather simple.
Using a 7812 IC, the delay timer can be powered from the existing 24V supply of the stabilizer.
Next, the delay relay N/O contacts may be wired in series with the stabilizer output socket wiring.
The above wiring would instantly take care of the issues as now the output would switch after some time during power witch ONs, allowing enough time for the internal relays to settle down with the correct voltages across their output contacts.
Friday, April 5, 2013
Make this Automatic 10 Watt to 1000 Watt LED Emergency Light Circuit
The following post explains a very simple yet an outstanding automatic 1 watt to 1000 watt emergency lamp circuit. The circuit also includes an automatic over voltage and low voltage battery shut off feature.
The entire circuit functioning may be understood with the following points:
Referring the below given circuit diagram, the transformer, bridge and the associated 100uF/25V capacitor forms a standard step down AC to DC power supply circuit.
The bottom SPDT relay is directly connected with the above power supply output such that it remains activated when mains is connected with the circuit.
In the above situation, the N/O contacts of the relay stay connected which keeps the LED shut OFF (since its connected with the N/C of the relay).
This takes care of the LED switching, making sure than the LEDs are switched ON only in the absence of mains power.
However, the positive from the battery is not directly connected with the LED module, rather it comes via another relay N/O contacts (the upper relay). This relay is integrated with a high/low voltage sensor circuit stationed for detecting the battery voltage conditions.
Supposing the battery is in a discharged condition, switching ON the mains keeps the relay deactivated so that the the rectified DC can reach the battery via the upper relay N/C contacts initiating the charging process of the connected battery.
When the battery voltages reaches the "full charge" potential, as per the setting of the 10 K preset, the relay trips and joins with the battery through its N/O contacts.
Now in the above situation if the mains fails, the LED module is able to get powered via the above relay and the lower relay N/O contacts and get illuminated.
Since relays are used, the power handling capacity becomes sufficiently high. The circuit is thus able to support in excess of 1000 watts of power (lamp), provided the relay contacts are appropriately rated for the preferred load.

The entire circuit functioning may be understood with the following points:
Referring the below given circuit diagram, the transformer, bridge and the associated 100uF/25V capacitor forms a standard step down AC to DC power supply circuit.
The bottom SPDT relay is directly connected with the above power supply output such that it remains activated when mains is connected with the circuit.
In the above situation, the N/O contacts of the relay stay connected which keeps the LED shut OFF (since its connected with the N/C of the relay).
This takes care of the LED switching, making sure than the LEDs are switched ON only in the absence of mains power.
However, the positive from the battery is not directly connected with the LED module, rather it comes via another relay N/O contacts (the upper relay). This relay is integrated with a high/low voltage sensor circuit stationed for detecting the battery voltage conditions.
Supposing the battery is in a discharged condition, switching ON the mains keeps the relay deactivated so that the the rectified DC can reach the battery via the upper relay N/C contacts initiating the charging process of the connected battery.
When the battery voltages reaches the "full charge" potential, as per the setting of the 10 K preset, the relay trips and joins with the battery through its N/O contacts.
Now in the above situation if the mains fails, the LED module is able to get powered via the above relay and the lower relay N/O contacts and get illuminated.
Since relays are used, the power handling capacity becomes sufficiently high. The circuit is thus able to support in excess of 1000 watts of power (lamp), provided the relay contacts are appropriately rated for the preferred load.

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